Varargs java

public static void printNumberOfArguments(int... numbers) {
    System.out.println(numbers.length);
}
printNumberOfArguments(1);
printNumberOfArguments(1, 2);
printNumberOfArguments(1, 2, 3);
printNumberOfArguments(new int[] { }); // no arguments here
printNumberOfArguments(new int[] { 1, 2 });

Varargs java

If a method has more than one parameter, the vararg parameter must be the last one in the declaration of the method

Varargs java

varargs:
It's possible to pass an arbitrary number of the same type arguments to 
a method using the special syntax named varargs (variable-length arguments).
 (Varargs can be used when we are unsure about the number of 
 arguments to be passed in a method)
Use varargs for any method (or constructor) that needs an array of
T (whatever type T may be) as input
One good example is String.format.
The format string can accept any number of parameters.

Similar codes

0 vote233 views1 answer
Barcode design in postgresql
Java
0 vote244 views1 answer
Send keybord key P in selenium java
Java
2 votes228 views4 answers
Class in java
Java
0 vote260 views1 answer
Java to kotlin converter android studio
Java
5 votes233 views1 answer
Could not initialize class org.codehaus.groovy.vmplugin.VMPluginFactory
Java
0 vote231 views1 answer
How good at you are at java
Java
0 vote252 views2 answers
Java choose random enum
Java
0 vote244 views1 answer
Which of the following is an example of a Method reference?
Java
0 vote237 views1 answer
How to use setonclicklistener from custom view in android
Java
0 vote230 views1 answer
Iterade dict javacirpt
Java