Varargs java

public static void printNumberOfArguments(int... numbers) {
    System.out.println(numbers.length);
}
printNumberOfArguments(1);
printNumberOfArguments(1, 2);
printNumberOfArguments(1, 2, 3);
printNumberOfArguments(new int[] { }); // no arguments here
printNumberOfArguments(new int[] { 1, 2 });

Varargs java

If a method has more than one parameter, the vararg parameter must be the last one in the declaration of the method

Varargs java

varargs:
It's possible to pass an arbitrary number of the same type arguments to 
a method using the special syntax named varargs (variable-length arguments).
 (Varargs can be used when we are unsure about the number of 
 arguments to be passed in a method)
Use varargs for any method (or constructor) that needs an array of
T (whatever type T may be) as input
One good example is String.format.
The format string can accept any number of parameters.

Similar codes

0 vote289 views1 answer
Adding entity to calenderfx
Java
0 vote245 views2 answers
How to remove all components from layeredPane java
Java
6 votes260 views3 answers
Remove part of string java
Java
0 vote248 views1 answer
String to pojo java
Java
1 vote256 views3 answers
Javafx textarea size
Java
0 vote244 views1 answer
How to catch enter key in java text field
Java
2 votes304 views1 answer
Link to method javadoc
Java
1 vote231 views1 answer
Java pointer
Java
0 vote261 views2 answers
Inheritance setter and getter in java
Java
2 votes245 views2 answers
Java convert float to double
Java