Varargs java

public static void printNumberOfArguments(int... numbers) {
    System.out.println(numbers.length);
}
printNumberOfArguments(1);
printNumberOfArguments(1, 2);
printNumberOfArguments(1, 2, 3);
printNumberOfArguments(new int[] { }); // no arguments here
printNumberOfArguments(new int[] { 1, 2 });

Varargs java

If a method has more than one parameter, the vararg parameter must be the last one in the declaration of the method

Varargs java

varargs:
It's possible to pass an arbitrary number of the same type arguments to 
a method using the special syntax named varargs (variable-length arguments).
 (Varargs can be used when we are unsure about the number of 
 arguments to be passed in a method)
Use varargs for any method (or constructor) that needs an array of
T (whatever type T may be) as input
One good example is String.format.
The format string can accept any number of parameters.

Similar codes

1 vote149 views1 answer
Localdate get last day of month java
Java
0 vote196 views2 answers
Replacing string with dynamic avalues java
Java
0 vote180 views1 answer
What is deserialization in java
Java
0 vote178 views1 answer
Kotlin registerForActivityResult
Java
1 vote216 views1 answer
Get drawable with string android java
Java
0 vote193 views2 answers
Write code to declare an array that will hold calendar months (.e. January to December) java
Java
0 vote202 views1 answer
How to put string in char array in java tutorialspoint
Java
1 vote190 views1 answer
Byte to bufferedimage java
Java
1 vote227 views1 answer
Jda embed message
Java
1 vote193 views1 answer
Java print array of objects
Java