/Python/How can I sort a dictionary in python according to its values?

How can I sort a dictionary in python according to its values?

s = {1: 1, 7: 2, 4: 2, 3: 1, 8: 1}
k = dict(sorted(s.items(),key=lambda x:x[0],reverse = True))
print(k)

Sort dict by value

x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
{k: v for k, v in sorted(x.items(), key=lambda item: item[1])}
{0: 0, 2: 1, 1: 2, 4: 3, 3: 4}

Source: stackoverflow.com

How to sort a dictionary py

orders = {
	'cappuccino': 54,
	'latte': 56,
	'espresso': 72,
	'americano': 48,
	'cortado': 41
}

sort_orders = sorted(orders.items(), key=lambda x: x[1], reverse=True)

for i in sort_orders:
	print(i[0], i[1])

Source: careerkarma.com

Similar codes

1 vote102 views1 answer
Get int value of char python
Python
0 vote115 views1 answer
Yield value from csv file python
Python
0 vote112 views1 answer
Python get cookie from browser
Python
17 votes111 views2 answers
Python calculate factorial
Python
0 vote129 views1 answer
RuntimeError: Tensor for 'out' is on CPU, Tensor for argument #1 'self' is on CPU, but expected them to be on GPU
Python
16 votes107 views3 answers
Python get all file names in a dir
Python
0 vote114 views1 answer
Django rest framework default_authentication_classes
Python
17 votes65 views5 answers
Read data from csv python
Python
-1 vote122 views1 answer
Getting a column that corresponds to the average of two columns in pandas
Python
0 vote116 views1 answer
How to add a command to button in a loop tkinter python
Python