/TypeScript/Get arguments from url flask

Get arguments from url flask

from flask import request

@app.route(...)
def login():
    username = request.args.get('username')
    password = request.args.get('password')

Source: stackoverflow.com

Flask get with parameters

from flask import request

@app.route('/my-route')
def my_route():
  page = request.args.get('page', default = 1, type = int)
  filter = request.args.get('filter', default = '*', type = str)

Source: stackoverflow.com

Similar codes

1 vote261 views1 answer
Next api typescript
TypeScript
1 vote284 views1 answer
Typescript switch test per case
TypeScript
1 vote254 views1 answer
Ion modal dismiss
TypeScript
8 votes270 views2 answers
Remove duplicates objects from array angular
TypeScript
0 vote265 views1 answer
Correct this attempt to modify "product" or use "let" in its declaration. [+1 location]
TypeScript
1 vote262 views1 answer
No provider for ChildrenOutletContexts Angular
TypeScript
0 vote252 views2 answers
Custom fonts vue
TypeScript
0 vote264 views1 answer
How to read web page in type script
TypeScript
0 vote251 views1 answer
Angular 6 checkbox checked dynamically
TypeScript
3 votes250 views1 answer
Typescript string contains
TypeScript