/Python/Sort list of dictionaries python by value

Sort list of dictionaries python by value

newlist = sorted(list_to_be_sorted, key=lambda k: k['name'])

How to sort a dictionary by value in python

import operator
x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
sorted_x = sorted(x.items(), key=operator.itemgetter(1))


# Sort by key
import operator
x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
sorted_x = sorted(x.items(), key=operator.itemgetter(0))

Python sort a dictionary by values

x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}

sort_by_key = dict(sorted(x.items(),key=lambda item:item[0]))
sort_by_value = dict(sorted(x.items(), key=lambda item: item[1]))

print("sort_by_key:", sort_by_key)
print("sort_by_value:", sort_by_value)

# sort_by_key: {0: 0, 1: 2, 2: 1, 3: 4, 4: 3}
# sort_by_value: {0: 0, 2: 1, 1: 2, 4: 3, 3: 4}

Python sort array of dictionary by value

my_list = sorted(my_list, key=lambda k: k['name'])

Source: stackoverflow.com

Similar codes

0 vote366 views1 answer
Python collections cheat sheet
Python
72 votes335 views6 answers
Python loop array
Python
0 vote366 views1 answer
This figure includes axes that are not compatible with tight_layout, so results might be incorrect
Python
0 vote333 views1 answer
Staticmethod vs classmethod python
Python
0 vote362 views1 answer
Def f(x) python
Python
0 vote313 views1 answer
Bag of word scikit learn
Python
0 vote319 views1 answer
Python test mock class method
Python
3 votes389 views1 answer
Python delete saved image
Python
2 votes314 views1 answer
Django.core.exceptions.ImproperlyConfigured
Python
0 vote331 views1 answer
How to kill a script if error is hit python
Python