Nth root of a number python

## How this will work is it takes the n to the power -1 root of num
## n to the power -1 is just 1 over n

def root(num, n):
  return a**(n**-1)

print(root(27, 3))

Find nth root of m using python

def nthrootofm(a,n):
    return pow(a,(1/n))
a=81
n=4
q=nthrootofm(a,n)
print(q)

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