Php mysql prepare query

$stmt = $mysqli->prepare("SELECT * FROM myTable WHERE name = ? AND age = ?");
$stmt->bind_param("si", $_POST['name'], $_POST['age']);
$stmt->execute();
$stmt->close();

Source: websitebeaver.com

Similar codes

1 vote101 views1 answer
Get input data in php
PHP
0 vote107 views1 answer
Parse json nested array form url in php
PHP
1 vote76 views1 answer
Twig replace char in string
PHP
0 vote119 views1 answer
How do I display logged-in username IF logged-in? site:wordpress.stackexchange.com
PHP
0 vote129 views1 answer
Codeigniter echo set content type
PHP CodeIgniter
0 vote99 views1 answer
Laravel eloquent save method return value
PHP
0 vote149 views1 answer
Count array index foreach in php
PHP
4 votes107 views5 answers
Removing index.php in codeigniter
PHP
4 votes109 views1 answer
Types of method in api
PHP
0 vote129 views1 answer
Env clear cache laravel
PHP Laravel