Python sort dictionary by value

How can I sort a dictionary in python according to its values?

s = {1: 1, 7: 2, 4: 2, 3: 1, 8: 1}
k = dict(sorted(s.items(),key=lambda x:x[0],reverse = True))
print(k)

Sort list of dictionaries python by value

newlist = sorted(list_to_be_sorted, key=lambda k: k['name'])

How to sort a dictionary by value in python

import operator
x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
sorted_x = sorted(x.items(), key=operator.itemgetter(1))


# Sort by key
import operator
x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
sorted_x = sorted(x.items(), key=operator.itemgetter(0))

Python sort a dictionary by values

x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}

sort_by_key = dict(sorted(x.items(),key=lambda item:item[0]))
sort_by_value = dict(sorted(x.items(), key=lambda item: item[1]))

print("sort_by_key:", sort_by_key)
print("sort_by_value:", sort_by_value)

# sort_by_key: {0: 0, 1: 2, 2: 1, 3: 4, 4: 3}
# sort_by_value: {0: 0, 2: 1, 1: 2, 4: 3, 3: 4}

Python sort dictionary by value

from operator import itemgetter
new_dict = sorted(data.items(), key=itemgetter(1))

Python - sort dictionary by value

d = {'one':1,'three':3,'five':5,'two':2,'four':4}

# Sort
a = sorted(d.items(), key=lambda x: x[1])

# Reverse sort
r = sorted(d.items(), key=lambda x: x[1], reverse=True)

Source: stackoverflow.com

Similar codes

1 vote306 views4 answers
Binary search tree in python
Python
0 vote312 views2 answers
Insert character into string at position x python
Python
0 vote407 views1 answer
Python String to array using list() method
Python
1 vote314 views3 answers
How to access variable of one function in another function in python
Python
5 votes324 views3 answers
Argparse list
Python
2 votes306 views1 answer
Numpy how to slice individual columns
Python
0 vote362 views1 answer
Multigreading sys.exit does not work
Python
0 vote332 views1 answer
Numpy declare arraylength
Python
0 vote353 views1 answer
Then generate Django project from the project template of cookiecutter
Python
1 vote345 views1 answer
Model checkpoint keras
Python