/Python/Cyclically rotate an array by one

Cyclically rotate an array by one

def rotate( arr, n):
    a[0],a[1:]=a[-1],a[:n-1]
    
#Driver Code    
a=[-1,2,3,7,5]
rotate(a,len(a))
print(a)
#Output: [5, -1, 2, 3, 7]

Cyclically rotate an array by one

# Python3 code for program to
# cyclically rotate an array by one
 
# Method for rotation
def rotate(arr, n):
    x = arr[n - 1]
     
    for i in range(n - 1, 0, -1):
        arr[i] = arr[i - 1];
         
    arr[0] = x;
 
 
# Driver function
arr= [1, 2, 3, 4, 5]
n = len(arr)
print ("Given array is")
for i in range(0, n):
    print (arr[i], end = ' ')
 
rotate(arr, n)
 
print ("\nRotated array is")
for i in range(0, n):
    print (arr[i], end = ' ')
 
# This article is contributed
# by saloni1297

Source: geeksforgeeks.org

Similar codes

22 votes211 views6 answers
Sort key python
Python
15 votes226 views3 answers
How to delete in python
Python
10 votes197 views2 answers
How to use modulo in python
Python
5 votes217 views3 answers
How to add button in tkinter
Python
1 vote302 views1 answer
Need Clang >= 7 to compile Filament from source
Python
0 vote217 views1 answer
Np.loadtext
Python
9 votes211 views2 answers
Python listen to keyboard input
Python
0 vote233 views1 answer
How to add value in array django
Python Django
0 vote241 views1 answer
Join mulitple dataframe pandas index
Python
0 vote209 views1 answer
Check if back is pressed python
Python