Argparse list

Argeparse can it take a type list

import argparse

parser = argparse.ArgumentParser()

# By default it will fail with multiple arguments.
parser.add_argument('--default')

# Telling the type to be a list will also fail for multiple arguments,
# but give incorrect results for a single argument.
parser.add_argument('--list-type', type=list)

# This will allow you to provide multiple arguments, but you will get
# a list of lists which is not desired.
parser.add_argument('--list-type-nargs', type=list, nargs='+')

# This is the correct way to handle accepting multiple arguments.
# '+' == 1 or more.
# '*' == 0 or more.
# '?' == 0 or 1.
# An int is an explicit number of arguments to accept.
parser.add_argument('--nargs', nargs='+')

# To make the input integers
parser.add_argument('--nargs-int-type', nargs='+', type=int)

# An alternate way to accept multiple inputs, but you must
# provide the flag once per input. Of course, you can use
# type=int here if you want.
parser.add_argument('--append-action', action='append')

# To show the results of the given option to screen.
for _, value in parser.parse_args()._get_kwargs():
    if value is not None:
        print(value)

Source: stackoverflow.com

Python argparser flags

parser.add_argument("-v", "--verbose", action="store_true",
                    help="verbose output")

Argparse list

parser.add_argument('-l','--list', nargs='+', help='<Required> Set flag', 
                    required=True)
# Use like:
# python arg.py -l 1234 2345 3456 4567

parser.add_argument('-l','--list', action='append', help='<Required> Set flag', 
                    required=True)
# Use like:
# python arg.py -l 1234 -l 2345 -l 3456 -l 4567

'''
Notes: 
1. nargs='+' takes 1 or more arguments, nargs='*' takes zero or more.
2. Don't use type=list!!! - There is probably no situation where you would want
   to use type=list with argparse. Ever.
'''

Source: stackoverflow.com

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