Label encoder python

from sklearn.preprocessing import LabelEncoder
encoder = LabelEncoder()

# apply on df
df['status'] = encoder.fit_transform(df['status'])
# can allso use the pandas.map
df['status'] = df['status'].map(lambda x: 1 if x=='Placed' else 0)

#apply on np.array
ct = ColumnTransformer(transformers=[('encoder', OneHotEncoder(), [1])], remainder='passthrough')
X = np.array(ct.fit_transform(X))

Label encoding

from sklearn.preprocessing import LabelEncoder

le = LabelEncoder()
companydata.ShelveLoc = le.fit_transform(companydata.ShelveLoc)

Similar codes

1 vote410 views2 answers
Redirect to the same page django
Python Django
0 vote324 views1 answer
Python x,y,z is d (20, 30, False)
Python
0 vote331 views1 answer
Kivy display PIL image
Python
3 votes352 views3 answers
Python codes
Python
0 vote310 views1 answer
Create requirements file and load it in new envirnment.
Python
0 vote324 views1 answer
Im save to a bytes io python
Python
0 vote335 views1 answer
Python string name out of mail
Python
0 vote292 views9 answers
Python code checker and corrector
Python
9 votes330 views6 answers
Python text to speech
Python
0 vote344 views1 answer
Pass context data with templateview in django
Python Django