Armstrong number in cpp

// armstrong or not

#include <iostream>
#include <math.h>
using namespace std;

int main()
{
    int num, temp, i, j, rem, sum=0, power=0;

    cout<< "Enter the number: ";
    cin>> num;

    temp = num;

    for(i=1; temp!=0; i++)
    {
        rem = temp % 10;
        for(j=0; j<10;j++)
        {
            if (rem == j)
                power++;
        }
        temp = temp / 10;
    }

    temp = num;

    for(i=1; temp!=0; i++)
    {
        rem = temp % 10;
        sum = sum + pow(rem, power);
        temp = temp / 10;
    }


    if(sum == num)
        cout<< "armstrong" ;
    else
        cout<< "Not armstrong";

    return 0;
}

Similar codes

0 vote174 views2 answers
344. Reverse String c++
C++
0 vote153 views3 answers
C++ comment
C++
2 votes189 views1 answer
How to delete a node c++
C++
1 vote176 views1 answer
Summary a long walk to water
C++
0 vote170 views1 answer
Is variable sized array are not allowed in c++?
C++
3 votes165 views1 answer
C++ check if string is empty
C++
30 votes128 views10 answers
While loop c++
C++
19 votes163 views3 answers
File reading c++
C++
1 vote171 views1 answer
Regex for phone number c++
C++
1 vote171 views3 answers
Cout in c++
C++