/Python/Python extract zip file without directory structure

Python extract zip file without directory structure

Python zip extract directory

import zipfile

archive = zipfile.ZipFile('archive.zip')

for file in archive.namelist():
    if file.startswith('foo/'):
        archive.extract(file, 'destination_path')

Source: stackoverflow.com

Python extract zip file without directory structure

import os
import shutil
import zipfile

my_dir = r"D:\Download"
my_zip = r"D:\Download\my_file.zip"

with zipfile.ZipFile(my_zip) as zip_file:
    for member in zip_file.namelist():
        filename = os.path.basename(member)
        # skip directories
        if not filename:
            continue

        # copy file (taken from zipfile's extract)
        source = zip_file.open(member)
        target = open(os.path.join(my_dir, filename), "wb")
        with source, target:
            shutil.copyfileobj(source, target)

Source: stackoverflow.com

How to extract zip file using python

ZipFile.extractall(path=None, members=None, pwd=None)

Source: thispointer.com

Similar codes

0 vote282 views1 answer
Link python3 to python3.7
Python
0 vote270 views1 answer
How to navigate to a sub html script selenium python
Python
5 votes287 views2 answers
Conda install spacy
Python
0 vote267 views2 answers
How to increment a variable in python]
Python
0 vote270 views1 answer
Copy multiple files from one folder to another folder
Python
0 vote306 views1 answer
Django loop through form errors
Python Django
4 votes256 views4 answers
Python save output to file
Python
0 vote265 views1 answer
Check if a word is a noun python
Python
0 vote281 views1 answer
Multiprocessing module in python
Python
0 vote270 views1 answer
Save model with best validation loss keras
Python