/Python/How to check if a number is a perfect square python

How to check if a number is a perfect square python

Check if a number is perfect cube in python

x = int(input())
print(int(round(x ** (1. / 3))) ** 3 == x)

How to check if a number is a perfect square python

import math

# Taking the input from user
number = int(input("Enter the Number"))

root = math.sqrt(number)
if int(root + 0.5) ** 2 == number:
    print(number, "is a perfect square")
else:
    print(number, "is not a perfect square")

Source: djangocentral.com

Python num perfect squares

print(int(int(n)**.5))

Similar codes

0 vote417 views1 answer
Django serializer exclude fields
Python
0 vote309 views1 answer
Numpy compute mad
Python
1 vote362 views2 answers
Assigning crs using python pyproj
Python
4 votes403 views1 answer
How to get the parent class using super python
Python
1 vote357 views1 answer
ModuleNotFoundError: No module named 'transforms3d'
Python
6 votes370 views4 answers
To_frame pandas
Python
0 vote338 views1 answer
Solve linear equation with np.linalg.solve
Python
12 votes380 views3 answers
Python pandas read_csv tsv
Python
1 vote348 views2 answers
Keras sequential layer
Python
1 vote336 views1 answer
Python head function show all columns
Python