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How to check if a number is a perfect square python

Check if a number is perfect cube in python

x = int(input())
print(int(round(x ** (1. / 3))) ** 3 == x)

How to check if a number is a perfect square python

import math

# Taking the input from user
number = int(input("Enter the Number"))

root = math.sqrt(number)
if int(root + 0.5) ** 2 == number:
    print(number, "is a perfect square")
else:
    print(number, "is not a perfect square")

Source: djangocentral.com

Python num perfect squares

print(int(int(n)**.5))

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