/Python/Python sort a list by a custom order

Python sort a list by a custom order

# Example usage:
list_to_sort = [('U', 23), ('R', 42), ('L', 17, 'D')]
custom_sort_order = ['R', 'D', 'L', 'U']
sorted(list_to_sort, key=lambda list_to_sort: custom_sort_order.index(list_to_sort[0]))
# Where 0 is the tuple index to use for sorting by custom order
--> [('R', 42), ('L', 17, 'D'), ('U', 23)]

Source: stackoverflow.com

Similar codes

10 votes340 views4 answers
Opencv resize image
Python
0 vote364 views1 answer
From flask import Flask app = Flask(__name__) @app.route('/',methods = ('GET')) def home(): return ('Hello World!!1') if __name__== '_main_': app.run()
Python Flask
0 vote333 views1 answer
Python random randint string
Python
0 vote368 views1 answer
Py regex if .jpg
Python
0 vote334 views1 answer
Bounding box python
Python
0 vote311 views1 answer
Pycaw , Python Audio Control Lib
Python
1 vote328 views1 answer
ImportError: dynamic module does not define module export function
Python
0 vote320 views1 answer
Controlliing a fill pattern in matplotlib
Python
-1 vote317 views2 answers
How to upgrade bash on mac
Python
1 vote337 views1 answer
Keras ensure equal class representation during traingin
Python