/Python/Python sort a list by a custom order

Python sort a list by a custom order

# Example usage:
list_to_sort = [('U', 23), ('R', 42), ('L', 17, 'D')]
custom_sort_order = ['R', 'D', 'L', 'U']
sorted(list_to_sort, key=lambda list_to_sort: custom_sort_order.index(list_to_sort[0]))
# Where 0 is the tuple index to use for sorting by custom order
--> [('R', 42), ('L', 17, 'D'), ('U', 23)]

Source: stackoverflow.com

Similar codes

1 vote212 views1 answer
Python reference script directory
Python
1 vote245 views1 answer
Django group by date from datetime field
Python Django
2 votes261 views2 answers
How to make a clock in python 3
Python
5 votes235 views3 answers
Update in django orm
Python Django
0 vote264 views1 answer
Python timedelta get days with fraction
Python
0 vote213 views1 answer
Python animation
Python
0 vote227 views2 answers
How to use django-filters with viewset
Python
186 votes244 views6 answers
Pip upgrade command
Python
3 votes230 views1 answer
How to close an application from python
Python
-1 vote230 views2 answers
Pandas print groupby
Python