/Python/Python sort a list by a custom order

Python sort a list by a custom order

# Example usage:
list_to_sort = [('U', 23), ('R', 42), ('L', 17, 'D')]
custom_sort_order = ['R', 'D', 'L', 'U']
sorted(list_to_sort, key=lambda list_to_sort: custom_sort_order.index(list_to_sort[0]))
# Where 0 is the tuple index to use for sorting by custom order
--> [('R', 42), ('L', 17, 'D'), ('U', 23)]

Source: stackoverflow.com

Similar codes

0 vote386 views1 answer
Boolean indexing datetime object | converting string to datetime object
Python
0 vote330 views1 answer
Array must not contain infs or NaNs
Python
5 votes341 views1 answer
Random forest regressor python
Python
2 votes372 views4 answers
How to create dictionary in python from csv
Python
1 vote392 views1 answer
Browser pop up yes no selenium python
Python
0 vote346 views1 answer
Split list on every nth element python
Python
2 votes349 views1 answer
Add hour minutes second python
Python
4 votes317 views3 answers
Python indexing
Python
0 vote360 views1 answer
Python savefig full screen
Python
0 vote352 views1 answer
Change group box border color pyqt5
Python