Tkinter filedialog filename

Python tkinter filedialog

from tkinter import filedialog

						# Where it open to.					# What the window is called.	# What file types the user can choose between. first one is the defualt. (("what ever", "*.format"), ("what ever 2", "*.format2"))
filedialog.askopenfilename(initialdir=os.path.normpath("C://"), title="Example", filetypes =(("PNG", "*.png"),("JPG", "*.jpg"),("All Files","*.*")))

Python tkinter filedialog folder

from tkinter import filedialog

								# Where it open to.					# What the window is called.
folder = filedialog.askdirectory(initialdir=os.path.normpath("C://"), title="Example")

Tkinter filedialog filename

def open_file():
    file = askopenfile(mode='r', filetypes=[
                       ('Text files', '*.txt'), ('CSV Files', '*.csv')])
    if file is not None:
        print(file.name.split("/")[-1]) # this will print the file name

btn = Button(root, text='Open', command=lambda: open_file())
btn.pack(side=TOP, pady=10)

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