Php fetch mysql result as variable

<?php
$result = mysql_query("SELECT id,email FROM people WHERE id = '42'");
if (!$result) {
    echo 'Could not run query: ' . mysql_error();
    exit;
}
?>

Source: stackoverflow.com

Similar codes

1 vote306 views2 answers
Page expire in laravel
PHP
1 vote297 views1 answer
Get post order by meta value int
PHP
8 votes272 views2 answers
Laravel password hash online
PHP Laravel
0 vote329 views1 answer
Make model inside module laravel
PHP Laravel
0 vote280 views1 answer
Laravel error reporting code for view
PHP
6 votes276 views1 answer
Wordpress get_date
PHP
-1 vote315 views2 answers
Php rtrim
PHP
13 votes280 views4 answers
Laravel hash
PHP
4 votes293 views4 answers
Php artisan drop table
PHP
1 vote289 views2 answers
Laravel eloquent join two models
PHP