Python even or odd

How to check if a number is odd python

num = int(input("Enter a number: "))  
if (num % 2) == 0:  
   print("{0} is Even number".format(num))  
else:  
   print("{0} is Odd number".format(num))

Source: javatpoint.com

Program to find even numbers in python

m = int(input("Enter number"))
if m % 2 == 0:
    print(m,"is an even number")
else:
    print(m,"is an odd number")

How to find if a value is even or odd in python

num = int(input("Enter a Number:"))
if num % 2 == 0:
  print(num , "is even")
else:
  print(num , "is odd")

How to make a python program on odd and even

Number = int(input("Write any number:- "))
Opration = Number%2
if Opration == 0:
    print("it's odd number")
else:
    print("It's even number")

Finding odd even python

number = int(input("Write a number:- "))
if number%2 == 0:
    print("Even number")
else:
    print("odd number")

Python even or odd

injd = int(input('Enter a number'))
n = injd % 2
if n > 0:
  print('This is an odd number')
else:
  print('This is an even number')

Similar codes

3 votes231 views1 answer
Selenium other item would revieve click
Python
16 votes227 views1 answer
Save model keras
Python
0 vote238 views1 answer
Break py
Python
0 vote259 views1 answer
Mean bias error
Python
0 vote248 views1 answer
Python try script
Python
1 vote246 views1 answer
Como deixar todas as letras maiusculas no python
Python
0 vote264 views2 answers
How to print aligned dictionary python
Python
0 vote233 views1 answer
How to invert a true false array in python
Python
74 votes243 views9 answers
Online python compiler
Python
3 votes311 views2 answers
Python check if list
Python