/Python/Django/Django create view filter options

Django create view filter options

class FolderForm(forms.ModelForm):
    class Meta:
       model = Folder
       fields = ['name', 'parent']

    def __init__(self, *args, **kwargs):
       user = kwargs.pop('user')
       super(FolderForm, self).__init__(*args, **kwargs)
       self.fields['parent'].queryset = Folder.objects.filter(user=user)

Source: stackoverflow.com

Django create view filter options

class FolderCreate(CreateView):
    template_name = 'Form/folder_create.html'
    form_class = FolderForm

    def get_form_kwargs(self):
        kwargs = super(FolderCreate, self).get_form_kwargs()
        kwargs['user'] = self.request.user
        return kwargs

Source: stackoverflow.com

Similar codes

0 vote481 views2 answers
From django.core.management import execute_from_command_line ImportError: No module named django.core.management
Python Django
1 vote329 views1 answer
Order by listview django
Python Django
0 vote369 views1 answer
Django command to fetch all columns of a table
Python Django
-1 vote371 views9 answers
Django for Beginners
Python Django
2 votes398 views1 answer
Auto datetime in django models
Python Django
1 vote377 views1 answer
Django link home page
Python Django
1 vote397 views1 answer
Hide particular attribute in django admin
Python Django
4 votes373 views2 answers
How to make django model field case insensitive
Python Django
0 vote383 views1 answer
How to compress image field in django?
Python Django
0 vote374 views1 answer
Django Signup form
Python Django