/Python/Apply numba to itertools import product

Apply numba to itertools import product

@nb.njit(nb.int32[:,:](nb.int32[:]))
def cproduct_idx(sizes: np.ndarray):
    """Generates ids tuples for a cartesian product"""
    assert len(sizes) >= 2
    tuples_count  = np.prod(sizes)
    tuples = np.zeros((tuples_count, len(sizes)), dtype=np.int32)
    tuple_idx = 0
    # stores the current combination
    current_tuple = np.zeros(len(sizes))
    while tuple_idx < tuples_count:
        tuples[tuple_idx] = current_tuple
        current_tuple[0] += 1
        # using a condition here instead of including this in the inner loop
        # to gain a bit of speed: this is going to be tested each iteration,
        # and starting a loop to have it end right away is a bit silly
        if current_tuple[0] == sizes[0]:
            # the reset to 0 and subsequent increment amount to carrying
            # the number to the higher "power"
            current_tuple[0] = 0
            current_tuple[1] += 1
            for i in range(1, len(sizes) - 1):
                if current_tuple[i] == sizes[i]:
                    # same as before, but in a loop, since this is going
                    # to get run less often
                    current_tuple[i + 1] += 1
                    current_tuple[i] = 0
                else:
                    break
        tuple_idx += 1
    return tuples

@nb.njit
def cartesian_product(*arrays):
    sizes = [len(a) for a in arrays]
    sizes = np.asarray(sizes, dtype=np.int32)
    tuples_count  = np.prod(sizes)
    array_ids = cproduct_idx(sizes)
    tuples = np.zeros((tuples_count, len(sizes)))
    for i in range(len(arrays)):
        tuples[:, i] = arrays[i][array_ids[:, i]]
    return tuples

@nb.njit
def cartesian_product_repeat(array, repeat):
    sizes = [len(array) for _ in range(repeat)]
    sizes = np.asarray(sizes, dtype=np.int32)
    tuples_count  = np.prod(sizes)
    array_ids = cproduct_idx(sizes)
    tuples = np.zeros((tuples_count, len(sizes)))
    for i in range(repeat):
        tuples[:, i] = array[array_ids[:, i]]
    return tuples

Source: stackoverflow.com

Similar codes

1 vote253 views2 answers
Location of python in cmd
Python
8 votes264 views6 answers
Redirect django
Python
0 vote281 views1 answer
Explorer gives new window
Python
0 vote238 views1 answer
Python ocr pdf dataframe
Python
1 vote254 views1 answer
Increase contrast cv2
Python
13 votes246 views3 answers
List remove method in python
Python
84 votes257 views2 answers
Python - save file
Python
1 vote273 views1 answer
How to use query_params in get_object djangorestframework
Python Django
5 votes251 views4 answers
Debugging in python
Python
31 votes243 views4 answers
Python remove nan rows
Python