/Python/Python sum of natural numbers recursion

Python sum of natural numbers recursion

Python recursive sum of digit

def sum_digits(num: int) -> int:
	
	#base case when your "positive" integer get to 0
    if num == 0: 
        return 0
    #base case when your "negative" integer get is between -10 and 0
    if num > -10 and num < 0:
        return num
	
	# recursion for positive integer
    elif num > 0:
        return (num % 10) + sum_digits(num//10)
	
	# recursion for negative integer
    elif num < 0:
        return -(abs(num) % 10) + sum_digits(-(abs(num)//10))
      
sum_digits(123) # returns 6
sum_digits(-123) # returns -6

Python sum of natural numbers recursion

# Python program to find the sum of natural using recursive function

def recur_sum(n):
   if n <= 1:
       return n
   else:
       return n + recur_sum(n-1)

# change this value for a different result
num = 16

if num < 0:
   print("Enter a positive number")
else:
   print("The sum is",recur_sum(num))


#Output - The sum is 210

Source: programiz.com

Similar codes

0 vote297 views1 answer
Row to column python numpy
Python
3 votes390 views2 answers
Django rest framework simple jwt
Python
0 vote327 views1 answer
Radians in python turtle
Python
3 votes325 views2 answers
Pandas apply return dataframe
Python
0 vote320 views1 answer
Split by backslash python
Python
1 vote358 views3 answers
Python is float function
Python
13 votes335 views4 answers
Pandas take first n rows
Python
0 vote311 views2 answers
Program to replace lower-case characters with upper-case and vice versa in python
Python
6 votes356 views5 answers
Manage.py", line 12, in main raise importerror( importerror: couldn't import django. are you sure it's installed and available on your pythonpath environment variable? did you forget to activate a virtual environment
Python Django
0 vote405 views1 answer
Case insensitive replace python
Python