/C/How to declare an array of n numbers in c

How to declare an array of n numbers in c

Array value from user c

#include <stdio.h>
int main(void)
{
int size, i;
printf("Enter the size of the arrays:\n");
scanf("%d", &size);

int arr1[size];
printf("Enter the elements of the array:\n");
for (i = 0; i < size; i++) {
    scanf_s("%d", arr1[size]);
}
printf("The current array is:\n %d", arr1[i]);
}

Source: stackoverflow.com

How to declare an array of n numbers in c

#include<stdio.h>
int main()
{
   int i,n;
   printf("Enter size of array:\n");
   scanf("%d",&n);
   int A[n];
   for (i=0; i<n; i++) {
   scanf("%d",&A[i]);
   }
   for (i=0; i<n; i++) {
   printf("%d",A[i]);
   }
}

Similar codes

2 votes106 views1 answer
Format bool c
C
0 vote116 views1 answer
Syntax of for loop in c stack over flow
C
2 votes106 views1 answer
C include uint8_t
C
3 votes100 views1 answer
Covertion of decimal into fraction
C
0 vote107 views1 answer
How to do Employing defensive code in the UI to ensure that the current frame is the most top level window
C
3 votes103 views2 answers
Gcc compiler for windows 10
C
0 vote104 views3 answers
Slick options
C
0 vote118 views1 answer
Transfer function exponent matlab
C
0 vote113 views1 answer
Increment & Decrement Operator in C language
C
0 vote108 views1 answer
Terraform fargate cpu
C