Fibonacci

Fibbonacci

0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, 233, 377, 610, 987, 1597, 2584, 4181, 6765, 10946, 17711, 28657, 46368, 75025, 121393, 196418, 317811,

Source: google.com

Fibonacci

# Easy fibonacci exercise
# Method #1
def fibonacci(n):
    # 1th: 0
    # 2th: 1
    # 3th: 1 ...
    if n == 1:
        return 0
    elif n == 2:
        return 1
    else:
        return fibonacci(n - 1) + fibonacci(n - 2)

# Method #2
def fibonacci2(n):
    if n == 0: return 0
    n1 = 1
    n2 = 1
    # (1, n - 2) because start by 1, 2, 3... not 0, 1, 1, 2, 3....
    for i in range(1, n - 2):
        n1 += n2
        n2 = n1 - n2
    return n1


print(fibonacci(13))
# return the nth element in the fibonacci sequence

Fibonacci

f(n) = f(n-1) + f(n-2) 
                                  f(6)
                                   ^
  			                       /\
                f(5)               +                       f(4)
                ^
               /\                   +                        /\
                
        f(4)    +           f(3)                     f(3)    +    f(2)
       ^                       ^                     ^              ^
      /\                       /\                    /\            /\
   
 f(3)   +       f(2)            f(2) +f(1)       f(2) + f(1)   f(1) +  f(0)             
   ^              ^                ^                ^
   /\             /\                /\              /\
    
f(2) + f(1)      f(1) +  f(0)     f(1)+ f(0)       f(1) + f(0)         
  ^
  /\
f(1) +  f(0) 
  
//f(6) = 8   ==>  f(1)*8    f(1) appears 8 times 
 double feb  = (1/Math.pow(5,0.5)) * (Math.pow((1+Math.pow(5,0.5))/2,n)) - (1/Math.pow(5,0.5))* (Math.pow((1-Math.pow(5,0.5))/2,n));  
  
f(1) == 1;

Fibonacci

def fibonacci(n):
    if n == 0:
        return 0
    elif n == 1:
        return 1
    return fibonacci(n - 1) + fibonacci(n - 2)

Source: dbader.org

Fibonacci

def fibonacci(n):
    if n <= 1:
        return n
    else:
        return fibonacci(n-1) + fibonacci(n-2)

limit = int(input("Insert the number of the values of the series that you would see: "))

for num in range(1, limit+1):
    print(fibonacci(num))

Source: programmareinpython.it

Fibonacci

Each test case will contains a single integer n where n >=1.

Source: codequotient.com

Similar codes

0 vote372 views1 answer
Sync_with_stdio
C++
2 votes335 views2 answers
C++ round number down
C++
5 votes331 views3 answers
Rand in C++
C++
1 vote374 views1 answer
How to take user input in a client server program in c++
C++
4 votes329 views3 answers
C plus
C++
0 vote365 views1 answer
Can derived class access base class non-static members without object of the base class
C++
0 vote324 views2 answers
C ++ splitlines
C++
0 vote358 views1 answer
For_each c++
C++
0 vote351 views1 answer
Array di struct
C++
3 votes340 views2 answers
Size of a matrix using vector c++
C++