Sed with variable

Sed replace with variable

Just concatenate var '"$var"' to replace values string in sed command:
$ sed -i 's/string_to_replace/'"$var"'/g' file_to_replace.txt

Sed with variable

sed -i "s/$var1/ZZ/g" "$file"

Source: askubuntu.com

Bash sed with variable

# If you want to store your regex in a bash variable 
# and use it in sed, you might need the following
BASE_REGEX="[0-9]{4}\.[0-9]+"
REGEX_ESCAPED=$(sed 's/[}{)(+]/\\&/g; s/\^/\\^/g' <<< "$BASE_REGEX")

# One variable can be used with sed
sed -i "s/${REGEX_ESCAPED}/REPLACEMENT/g" file.txt
# The other can be used with bash internal regex operator
if [[ "2022.42" =~ ^${BASE_REGEX}$ ]]
then
	echo 'Matches !'
fi

Similar codes

17 votes278 views3 answers
Start apache server in ubuntu
Shell/Bash
1 vote282 views1 answer
Force logrotate linux
Shell/Bash
0 vote301 views2 answers
Convert x-ray dicom to png
Shell/Bash
0 vote271 views1 answer
Install godaddy ssl certificate on aws ec2 instance
Shell/Bash
2 votes288 views2 answers
Generate key and certificate openssl
Shell/Bash
1 vote358 views1 answer
Create React App requires Node 14 or higher.
Shell/Bash
1 vote241 views1 answer
Git revert to commit hash
Shell/Bash
0 vote276 views1 answer
Zsh: command not found: protoc mac
Shell/Bash
0 vote265 views1 answer
Set up django-lint
Shell/Bash
0 vote285 views1 answer
Linux create user with expiration
Shell/Bash