/Python/Flask conditional according to urrl

Flask conditional according to urrl

<!DOCTYPE html>
<html>
<head>
    <title>Template</title>
</head>
<body>
    <h3>You are here: {{ request.path }}</h3>
    {% if request.path == url_for('show_funding') %}
        <script src="{{ url_for ('static', filename='js/funding.js')}}"></script>
    {% endif %}
</body>
</html>

Source: stackoverflow.com

Flask conditional according to urrl

from flask import Flask
from flask import request
from flask import render_template

app = Flask(__name__)

@app.route('/')
def show_index():
    return render_template('funding.html')

@app.route('/funding')
def show_funding():
    return render_template('funding.html')

if __name__ == '__main__':
    app.run(debug = True)

Source: stackoverflow.com

Similar codes

0 vote279 views1 answer
In pandas series hot to count the numer of appearences
Python
76 votes305 views6 answers
Python file open
Python
3 votes281 views3 answers
Pandas sum group by
Python
6 votes357 views2 answers
Flask form options
Python Flask
13 votes291 views6 answers
Range parameters python
Python
0 vote279 views1 answer
Python event start from file funcion
Python
2 votes319 views1 answer
Django model current timestamp
Python Django
10 votes295 views5 answers
Find nan values in a column pandas
Python
0 vote274 views1 answer
How to flatten the image dataset
Python
0 vote362 views1 answer
How to fix invalid salt in python flask
Python Flask