/Python/Numpy count occurrences in array

Numpy count occurrences in array

How to count occurences of a certain item in a numpy array

>>> import numpy as np
>>> y = np.array([1, 2, 2, 2, 2, 0, 2, 3, 3, 3, 0, 0, 2, 2, 0])

>>> np.count_nonzero(y == 1)
1
>>> np.count_nonzero(y == 2)
7
>>> np.count_nonzero(y == 3)
3

Source: stackoverflow.com

Count values in array python

a = numpy.array([0, 3, 0, 1, 0, 1, 2, 1, 0, 0, 0, 0, 1, 3, 4])
unique, counts = numpy.unique(a, return_counts=True)
dict(zip(unique, counts))

# {0: 7, 1: 4, 2: 1, 3: 2, 4: 1}

Source: stackoverflow.com

Numpy count occurrences in array

unique, counts = numpy.unique(a, return_counts=True)

Numpy count occurrences in interval array

# credit to Stack Overflow user in source link
# a is a numpy array
# Note: the following syntax allows you to count the number of elements x
# of the array such that 25 < x < 100 
((a > 25) & (a < 100)).sum()

Source: stackoverflow.com

Similar codes

0 vote354 views1 answer
Create chatbot in Python - Source: NAYCode.com
Python
0 vote316 views1 answer
Locust python use of between
Python
0 vote321 views1 answer
Python ufeff character from file
Python
0 vote367 views1 answer
Python local date time
Python
6 votes303 views1 answer
Anaconda python update packages
Python
3 votes305 views1 answer
Make length string in pandas
Python
0 vote318 views1 answer
Finite automaton in python
Python
1 vote321 views1 answer
How to change help command on discord python
Python
0 vote325 views2 answers
Notebook python static website generator
Python
9 votes294 views1 answer
Json formatter terminal
Python