How to print value of pointer in c

#include <stdio.h>
#include <stdlib.h>

void pointerFuncA(int* iptr){
/*Print the value pointed to by iptr*/
printf("Value:  %d\n", *iptr );

/*Print the address pointed to by iptr*/
printf("Value:  %p\n", iptr );

/*Print the address of iptr itself*/
printf("Value:  %p\n", &iptr );
}

int main(){
int i = 1234; //Create a variable to get the address of
int* foo = &i; //Get the address of the variable named i and pass it to the integer pointer named foo
pointerFuncA(foo); //Pass foo to the function. See I removed void here because we are not declaring a function, but calling it.

return 0;
}

Source: stackoverflow.com

Similar codes

0 vote439 views8 answers
Convert c program to assembly language online
C
0 vote376 views1 answer
Simple bootstrap form example
C
0 vote392 views1 answer
How to stop scanf from adding a new line in c
C
0 vote414 views1 answer
What happens if i acess a freed variable in c
C
1 vote398 views1 answer
Accessing elements of 1d array using pointers
C
10 votes432 views2 answers
Int num = (rand() % (upper - lower + 1)) + lower;
C
0 vote417 views2 answers
Sort linked list C
C
2 votes397 views5 answers
Arduino internal pull up resistor
C
0 vote418 views1 answer
Argparse allow line break
C
5 votes380 views1 answer
Type change in c
C