/Python/Python efficiently find duplicates in list

Python efficiently find duplicates in list

Count the duplicates in a list in python

some_list=['a','b','c','b','d','m','n','n']

 my_list=sorted(some_list)
 
duplicates=[]
for i in my_list:
     if my_list.count(i)>1:
         if i not in duplicates:
             duplicates.append(i)
 
print(duplicates)

How to check if there are duplicates in a list python

>>> your_list = ['one', 'two', 'one']
>>> len(your_list) != len(set(your_list))
True

Python efficiently find duplicates in list

from collections import Counter

def get_duplicates(array):
    c = Counter(array)
    return [k for k in c if c[k] > 1]

Source: stackoverflow.com

Similar codes

2 votes333 views2 answers
Python get pixel color from screen
Python
0 vote330 views1 answer
How to show bar loading in python in cmd
Python
0 vote337 views1 answer
Dataframe of one row
Python
1 vote331 views2 answers
Python read and write pdf data
Python
6 votes365 views2 answers
What is in the python built in namespace
Python
4 votes326 views1 answer
Python unlist flatten nested lists
Python
4 votes341 views2 answers
Django queryset group by
Python
0 vote367 views1 answer
Executing a python script interactively
Python
-1 vote319 views2 answers
If __name__ == '__main__': a = int(input()) b = int(input())
Python
0 vote333 views1 answer
Alexa python get slot value
Python