/Python/Flask/Flask arguments in url

Flask arguments in url

Get arguments from url flask

from flask import request

@app.route(...)
def login():
    username = request.args.get('username')
    password = request.args.get('password')

4

Source: stackoverflow.com

Flask arguments in url

@app.route('/<name>')
def my_view_func(name):
    return name

0

Source: stackoverflow.com

Similar codes

0 vote354 views1 answer
Flask No application found. Either work inside a view function or push an application context
Python Flask
1 vote309 views2 answers
Run flask in background
Python Flask
3 votes291 views3 answers
Import flask
Python Flask
1 vote292 views1 answer
Python flask display variable in html
Python Flask
2 votes301 views1 answer
Flask minimul app
Python Flask
4 votes311 views3 answers
How to change port in flask app
Python Flask
0 vote317 views1 answer
Supervisor gunicorn virtualenv flask
Python Flask
1 vote305 views1 answer
Return json with flask
Python Flask
1 vote301 views2 answers
Flask bootstrap
Python Flask
3 votes281 views3 answers
Flask migrate install
Python Flask

Share