Bash sed with variable

Sed with variable

sed -i "s/$var1/ZZ/g" "$file"

Source: askubuntu.com

Bash sed with variable

# If you want to store your regex in a bash variable 
# and use it in sed, you might need the following
BASE_REGEX="[0-9]{4}\.[0-9]+"
REGEX_ESCAPED=$(sed 's/[}{)(+]/\\&/g; s/\^/\\^/g' <<< "$BASE_REGEX")

# One variable can be used with sed
sed -i "s/${REGEX_ESCAPED}/REPLACEMENT/g" file.txt
# The other can be used with bash internal regex operator
if [[ "2022.42" =~ ^${BASE_REGEX}$ ]]
then
	echo 'Matches !'
fi

Similar codes

104 votes320 views4 answers
How to install deb file in kali linux
Shell/Bash
0 vote320 views1 answer
Find command absolute path
Shell/Bash
50 votes336 views2 answers
Linux os version
Shell/Bash
2 votes359 views3 answers
Disable ufw
Shell/Bash
0 vote339 views1 answer
Turn on bluetooth in kali linux / soft unblock
Shell/Bash
26 votes384 views5 answers
Install vlc ubuntu
Shell/Bash
1 vote326 views4 answers
Git delete tag
Shell/Bash
5 votes315 views6 answers
Laravel create project
Shell/Bash
0 vote323 views1 answer
Adoptopenjdk to linux docker image
Shell/Bash
61 votes345 views6 answers
Kill process on port windows
Shell/Bash