Selenium python login instagram

Instagram login with selenium py

driver.find_element_by_xpath("//input[@name='username']").send_keys(username)
driver.find_element_by_xpath("//input[@name='password']").send_keys(password)
driver.find_element_by_xpath("//button[contains(.,'Log in')]").click()

Selenium python login instagram

from selenium import webdriver
from selenium.webdriver.common.action_chains import ActionChains
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.by import By
from selenium.webdriver.support.wait import WebDriverWait

browser = webdriver.Chrome()
browser.get('https://www.instragram.com')

wait = WebDriverWait(browser, 10)

login_elem = browser.find_element_by_xpath(
   '//*[@id="react-root"]/section/main/article/div[2]/div[2]/p/a')

second_page_flag = wait.until(EC.presence_of_element_located(
    (By.CLASS_NAME, "KPnG0")))  # util login page appear


user = browser.find_element_by_name("username")

passw = browser.find_element_by_name('password')

ActionChains(browser)\
    .move_to_element(user).click()\
    .send_keys('test')\
    .move_to_element(passw).click()\
    .send_keys('test')\
    .perform()

login_button_ = browser.find_element_by_xpath(
    "//form[@class='HmktE']/div[3]/button")

login_button_.click()

Source: stackoverflow.com

Selenium python login instagram

from time import sleep
from selenium import webdriver
from selenium.webdriver.common.action_chains import ActionChains

browser = webdriver.Chrome()
browser.get('https://www.instragram.com')

login_elem = browser.find_element_by_xpath('//*[@id="react-root"]/section/main/article/div[2]/div[2]/p/a')
login_elem.click()

user = browser.find_element_by_name("username")

passw = browser.find_element_by_name('password')

ActionChains(browser)\
    .move_to_element(user).click()\
    .send_keys('test')\
    .move_to_element(passw).click()\
    .send_keys('test')\
    .perform()

login_button = browser.find_element_by_class_name(
'_0mzm- sqdOP  L3NKy       ')


login_button.click()

Source: stackoverflow.com

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