/Python/Count consecutive values in python

Count consecutive values in python

#count consecutif 1 in list. list exemple l=['1','1','0','1','0','1,'1',1']
cpt=0
    compte=[]
    for i in ch:
        if i=='1':
            cpt +=1
        else:
            compte.append(cpt)
            cpt=0
    compte.append(cpt)

Count consecutive values in python

>>> from itertools import groupby
>>> def groups(l):
...     return [sum(g) for i, g in groupby(l) if i == 1]
...
>>> groups([0,1,0,0,0])
[1]
>>> groups([0,0,1,1,0])
[2]
>>> groups([1,1,0,1,1])
[2, 2]

Similar codes

0 vote168 views2 answers
Django admin image
Python
0 vote165 views1 answer
Saving model
Python
0 vote177 views1 answer
Django file field from base64
Python Django
1 vote178 views1 answer
How to update a plot in tkinter\
Python
0 vote155 views1 answer
Save numpy arrayw with PIL
Python
0 vote166 views1 answer
Menu in python
Python
0 vote154 views1 answer
Reading a file line by line using a generator
Python
89 votes163 views6 answers
Sleep python
Python
1 vote208 views1 answer
Impute mode pandas
Python
4 votes211 views2 answers
Sum of array using recursion in python
Python