Pandas index between time

i = pd.date_range('2018-04-09', periods=4, freq='1D20min')
ts = pd.DataFrame({'A': [1, 2, 3, 4]}, index=i)
ts
                     A
2018-04-09 00:00:00  1
2018-04-10 00:20:00  2
2018-04-11 00:40:00  3
2018-04-12 01:00:00  4

ts.between_time('0:15', '0:45')
                     A
2018-04-10 00:20:00  2
2018-04-11 00:40:00  3

You get the times that are not between two times by setting start_time later than end_time:

ts.between_time('0:45', '0:15')
                     A
2018-04-09 00:00:00  1
2018-04-12 01:00:00  4

Source: stackoverflow.com

Similar codes

11 votes351 views3 answers
Shuffle dataframe python
Python
24 votes349 views2 answers
How to check the type of a variable in python
Python
25 votes344 views6 answers
Python check if list contains elements of another list
Python
11 votes323 views4 answers
Python excel file
Python
22 votes325 views5 answers
Define a string in python
Python
0 vote308 views1 answer
Classifier max_depth': (150, 155, 160),
Python
0 vote339 views1 answer
Dynamic grid using tkinter
Python
1 vote282 views1 answer
Add to empty string python
Python
39 votes335 views4 answers
Round off float to 2 decimal places in python
Python
89 votes315 views6 answers
Requirements.txt python
Python