Random string generator java

import java.util.Random;

public class Generator {
	public static String generateRandomPassword(int len) {
		String chars = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijk"
          +"lmnopqrstuvwxyz!@#$%&";
		Random rnd = new Random();
		StringBuilder sb = new StringBuilder(len);
		for (int i = 0; i < len; i++)
			sb.append(chars.charAt(rnd.nextInt(chars.length())));
		return sb.toString();
	}
}

Java random string

public static String getRandomString(int size) {
  	// The string that we will return
	String rand = "";
  	// The chars that are used to generate the random string
	String chars = "1234567890-=!@#$%^&*()_+qwertyuiop[]\\QWERTYUIOP{}|asdfghjkl;'ASDFGHJKL:\"zxcvbnm,./ZXCVBNM<>?";
  	// Loop based on the requested size
  	for (int i = 0; i < size; i++) {
      	// Add a random char from the chars string to the rand string
		rand += chars.toCharArray()[new Random().nextInt(chars.length())];
	}
  	// Return the random string
	return rand;
}

Generate 5 digit random string in java

RandomStringUtils.randomAlphanumeric(17).toUpperCase()

Source: stackoverflow.com

Similar codes

0 vote211 views1 answer
If statements not working java
Java
1 vote221 views4 answers
How to change color of drawable in android
Java
1 vote224 views1 answer
Java for schleife
Java
0 vote225 views1 answer
Intellij evaluate expression
Java
1 vote225 views1 answer
How to get array index value into variable in java
Java
0 vote228 views1 answer
Applescript copy to clipboard
Java
24 votes243 views3 answers
First java program
Java
0 vote247 views1 answer
Do not treat position as fixed; only use immediately and call `holder.getAdapterPosition()` to look it up later
Java
6 votes202 views1 answer
How to declare a constant in Java
Java
3 votes223 views3 answers
Spigot start.bat code
Java