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Python sort a list using defined order

Python sort a list using defined order

>>> sorted(A, key = lambda i: B.index(i[0]))
[[6, 1], [1, 3], [3, 5]]

0

Source: stackoverflow.com

Python sort a list using defined order

>>> A = [[3,5],[1,3],[6,1]]
>>> B = [6,1,3]
>>> srt = {b: i for i, b in enumerate(B)}
>>> sorted(A, key=lambda x: srt[x[0]])
[[6, 1], [1, 3], [3, 5]]

0

Source: stackoverflow.com

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