Python extract string

# string [start:end:step]
string = "freeCodeCamp"
print(string[0:len(string)-1])		# freeCodeCam
print(string[0:5])		            # freeC
print(string[2:6])		            # eeCo
print(string[-1])		            # p
print(string[-5:])		            # eCamp
print(string[1:-4])                 # reeCode
print(string[-5:-2])	            # eCa
print(string[::2])		            # feCdCm

Source: freecodecamp.org

Extract text regex python

>>> import re

>>> re.findall(r'\d{1,5}','gfgfdAAA1234ZZZuijjk')

>>> ['1234']

Similar codes

10 votes198 views6 answers
Declaring variables in python
Python
0 vote220 views1 answer
Jetson nx unable to install matplotlib
Python
2 votes163 views1 answer
Python loop list of dictionaries
Python
0 vote207 views1 answer
Id
Python
0 vote209 views1 answer
Feature importance plot
Python
0 vote225 views1 answer
I want only the span of finditer in re python
Python
15 votes177 views4 answers
How to stop python for some time in python
Python
2 votes244 views2 answers
Django regexvalidator example
Python Django
3 votes206 views1 answer
What is cpython
Python
1 vote200 views2 answers
Make python3 as default in linux
Python