Python extract string

# string [start:end:step]
string = "freeCodeCamp"
print(string[0:len(string)-1])		# freeCodeCam
print(string[0:5])		            # freeC
print(string[2:6])		            # eeCo
print(string[-1])		            # p
print(string[-5:])		            # eCamp
print(string[1:-4])                 # reeCode
print(string[-5:-2])	            # eCa
print(string[::2])		            # feCdCm

Source: freecodecamp.org

Extract text regex python

>>> import re

>>> re.findall(r'\d{1,5}','gfgfdAAA1234ZZZuijjk')

>>> ['1234']

Similar codes

0 vote286 views1 answer
App = Flask(_name_) NameError: name '_name_' is not defined
Python
0 vote320 views1 answer
How to customize simplejwt error response message in django restframework
Python Django
0 vote283 views1 answer
To obtain the latest released version of statsmodels using pip:
Python
0 vote310 views1 answer
Views.py django
Python Django
2 votes271 views2 answers
Pandas replace null values with values from another column
Python
4 votes289 views1 answer
Python: change column name
Python
3 votes267 views1 answer
Tf.squeeze()
Python
1 vote263 views1 answer
Python try/except loop
Python
29 votes284 views9 answers
Traduttore
Python
0 vote277 views1 answer
Python django model range validation
Python