Pyramid pattern in python

Pattern in python

rows = 6                        #Pattern(1,121,12321,1234321,123454321)
for i in range(1, rows + 1):
    for j in range(1, i - 1):
        print(j, end=" ")
    for j in range(i - 1, 0, -1):
        print(j, end=" ")
    print()

Pyramid pattern in python

n = 3
for i in range(1, n+1):
  print(f"{' '*(n-i)}{' *'*i}"[1:])
  
# Output:
#  *
# * *
#* * *

* pattern by python

def pattern(n):    
  for i in range(0,n):       
    for j in range(0, i+1): 
      print("* " , end="")         
      print("\r") pattern(5

Similar codes

26 votes175 views10 answers
For loop
Python
0 vote186 views3 answers
Gau mata
Python
0 vote184 views1 answer
Django array of dates
Python Django
1 vote172 views2 answers
Return programming
Python
16 votes171 views2 answers
Choice random python
Python
0 vote166 views1 answer
Python move mouse slowly
Python
44 votes176 views6 answers
Pandas read csv file
Python
0 vote171 views1 answer
Python list files only in given directory
Python
3 votes192 views1 answer
Find common words in two lists python
Python
2 votes149 views2 answers
Character in function python 3
Python