Freq count in python

freq = {} 
    for item in my_list: 
        if (item in freq): 
            freq[item] += 1
        else: 
            freq[item] = 1

List count frequency python

import collections
a = [1,1,1,1,2,2,2,2,3,3,4,5,5]
counter=collections.Counter(a)
print(counter)
# Counter({1: 4, 2: 4, 3: 2, 5: 2, 4: 1})
print(counter.values())
# [4, 4, 2, 1, 2]
print(counter.keys())
# [1, 2, 3, 4, 5]
print(counter.most_common(3))
# [(1, 4), (2, 4), (3, 2)]

Source: stackoverflow.com

Similar codes

52 votes367 views6 answers
Time it python
Python
0 vote378 views3 answers
Web scrape forex live prices
Python
3 votes372 views2 answers
Python extract specific columns from pandas dataframe
Python
0 vote366 views1 answer
Python ValueError: zero-size array to reduction operation maximum which has no identity
Python
0 vote349 views1 answer
How to type shashank in python
Python
122 votes328 views3 answers
Iterate through keys in dictionary
Python
89 votes336 views4 answers
New env in conda
Python
0 vote386 views1 answer
How to downgrade python 3.9 to 3.8
Python
1 vote348 views1 answer
Listing index elasticsearch python
Python
0 vote353 views3 answers
2 decimal places
Python