/Python/Python get command line arguments

Python get command line arguments

import sys
print("This is the name of the script:", sys.argv[0])
print("Number of arguments:", len(sys.argv))
print("The arguments are:" , str(sys.argv))

#Example output
#This is the name of the script: sysargv.py
#Number of arguments in: 3
#The arguments are: ['sysargv.py', 'arg1', 'arg2']

Source: pythonforbeginners.com

Pass argument to a py file

import sys

def hello(a,b):
    print "hello and that's your sum:", a + b

if __name__ == "__main__":
    a = int(sys.argv[1])
    b = int(sys.argv[2])
    hello(a, b)
# If you type : py main.py 1 5
# It should give you "hello and that's your sum:6"

Java read file from command line argument

import java.util.Scanner;
import java.io.File;
Scanner input = new Scanner(new File(args[0])); //Where args[0] is the cmd argument, the file name

Similar codes

0 vote190 views1 answer
Operator.itemgetter(1) in python
Python
24 votes197 views1 answer
Python datetime strptime hour minute second
Python
0 vote182 views1 answer
How to make a config txt file on python
Python
7 votes198 views3 answers
Pandas replace nonetype with empty string
Python
0 vote208 views1 answer
Django forms request
Python Django
0 vote200 views1 answer
Python http handler iis
Python
7 votes184 views1 answer
Create text channel discord.py
Python
0 vote189 views1 answer
The code panda
Python
12 votes254 views4 answers
How to add array in python
Python
0 vote193 views1 answer
Pickled list
Python