/Python/Intersection of 3 array in O(n) python

Intersection of 3 array in O(n) python

def intersection(A, B, C):
    '''
    Intersection of 3 array in O(n).
    '''
    i = j = k = 0
    len1 = len(A)
    len2 = len(B)
    len3 = len(C)
	
    while (i < len1 and j < len2 and k< len3):
        
        if (A[i] == B[j] and B[j] == C[k]):
            print(A[i])
            i += 1
            j += 1
            k += 1
        elif A[i] < B[j]:
            i += 1
        elif B[j] < C[k]:
            j += 1
        else:
            k += 1

Similar codes

7 votes199 views3 answers
Python get file extension from path
Python
0 vote199 views1 answer
Numpy datetime64 get day
Python
0 vote191 views2 answers
For with key value over numpy array py
Python
0 vote180 views1 answer
Poision in chinese
Python
1 vote188 views1 answer
Nlargest heapq
Python
2 votes180 views1 answer
Mongodb not in
Python
19 votes192 views1 answer
Get requests from python
Python
0 vote191 views1 answer
Convert pandas group to dict
Python
2 votes240 views3 answers
Get absolute url django
Python Django
8 votes186 views4 answers
Create an array with same value python
Python