Python concatenate dictionaries

Python merge dictionaries

dict1 = {'color': 'blue', 'shape': 'square'}
dict2 = {'color': 'red', 'edges': 4}

dict1.update(dict2) #if a key exists in both, it takes the value of the second dict
# dict1 = {'color': 'red', 'shape': 'square', 'edges': 4}
# dict2 is left unchanged

Python merge dictionaries

# Python >= 3.5:
def merge_dictionaries(a, b):
   return {**a, **b}
  
# else:
def merge_dictionaries(a, b):
    c = a.copy()   # make a copy of a 
    c.update(b)    # modify keys and values of a with the b ones
    return c

a = { 'x': 1, 'y': 2}
b = { 'y': 3, 'z': 4}
print(merge_dictionaries(a, b)) 		# {'y': 3, 'x': 1, 'z': 4}

Python merge dictionaries

def merge_dicts(dict1, dict2):
        """Here's an example of a for-loop being used abusively."""
        return {**dict2, **{k: (v if not (k in dict2) else (v + dict2.get(k)) if isinstance(v, list) else merge_dicts(v, dict2.get(k))) if isinstance(v, dict) else v for k, v in dict1.items()}}

Python concatenate dictionaries

# list_of_dictionaries contains a generic number of dictionaries
# having the same type of keys (str, int etc.) and type of values
global_dict = {}

for single_dict in list_of_dictionaries:
    global_dict.update(single_dict)

Concat dicts python

d1={1:2,3:4}; d2={5:6,7:9}; d3={10:8,13:22}
d4 = dict(d1, **d2); d4.update(d3)

-2

Source: stackoverflow.com

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