Python random phone number

import random

def phn():
    n = '0000000000'
    while '9' in n[3:6] or n[3:6]=='000' or n[6]==n[7]==n[8]==n[9]:
        n = str(random.randint(10**9, 10**10-1))
    return n[:3] + '-' + n[3:6] + '-' + n[6:]

Source: stackoverflow.com

Similar codes

1 vote363 views1 answer
Print(\'Test set predictions:\\n{}\'.format(y_pred))
Python
268 votes523 views0 answer
Last element of list python
Python
0 vote312 views1 answer
Pandas automatic allignment of columns
Python
0 vote328 views1 answer
Free download django app for windows 10
Python
13 votes322 views4 answers
If list item in string python
Python
2 votes319 views1 answer
Python how to check which int var is the greatest
Python
0 vote332 views1 answer
Button onclick message box in python tkinter
Python
4 votes320 views2 answers
Python wait until
Python
11 votes299 views6 answers
Venv activate windows
Python
0 vote350 views1 answer
Django populate database in view
Python