Python random phone number

import random

def phn():
    n = '0000000000'
    while '9' in n[3:6] or n[3:6]=='000' or n[6]==n[7]==n[8]==n[9]:
        n = str(random.randint(10**9, 10**10-1))
    return n[:3] + '-' + n[3:6] + '-' + n[6:]

Source: stackoverflow.com

Similar codes

15 votes361 views2 answers
Read excel into dataframe python
Python
0 vote316 views1 answer
Exponent function in python
Python
2 votes339 views1 answer
ValueError: Found array with dim 3. Estimator expected <= 2.
Python
1 vote334 views1 answer
Format number of digits python
Python
14 votes319 views1 answer
Sort list of dictionaries by key python
Python
2 votes332 views2 answers
Fillna string
Python
62 votes335 views6 answers
Sort dictionary by values
Python
3 votes379 views1 answer
Django import model from another app
Python Django
0 vote358 views1 answer
Python plot axis labels
Python
90 votes356 views6 answers
Python get current directory
Python