Group by in ruby mongoid

Lead.where(client_id: client.id.to_s).collection.aggregate([{"$group"=>{ :_id=> "$sales_id" , :count=>{"$sum"=>1} } }, {"$match": { count: { "$gte": 3 } }} ]).to_a

Similar codes

1 vote193 views1 answer
How to use if else to prove a variable even or odd in python
Python
0 vote263 views1 answer
How to compress image field in django?
Python
4 votes182 views2 answers
Maximize window in selenium
Python
2 votes198 views2 answers
Python do nothing
Python
0 vote211 views1 answer
Class indexing
Python
75 votes183 views3 answers
How to get a random element from an array in python
Python
5 votes184 views2 answers
Pip pandas
Python
0 vote197 views1 answer
Python csv delete all rows
Python
3 votes278 views1 answer
Modulenotfounderror: no module named 'png'
Python
0 vote198 views1 answer
Python force realod
Python