/Java/Compare two character alphabetically java

Compare two character alphabetically java

Java compare strings alphabetically

String a = "HYRE"; 
String b = "AGNYG";  

int compare = a.compareTo(b);  

if (compare < 0) {  
    //a is smaller
}
else if (compare > 0) {
    //a is larger 
}
else {  
    //a is equal to b
}

Compare two character alphabetically java

return Character.toLowerCase(ch1) < Character.toLowerCase(ch2);

Source: stackoverflow.com

Similar codes

-1 vote176 views2 answers
Access activity method from adapter
Java
3 votes139 views2 answers
Register listener spigot
Java
0 vote176 views1 answer
Stack overflow recyclerview
Java
0 vote190 views1 answer
How to reset jframe java swing
Java
6 votes128 views2 answers
Tostring java
Java
0 vote183 views1 answer
Variable is multiple of 3
Java
4 votes176 views4 answers
Java method
Java
1 vote188 views1 answer
Javadoc link to class
Java
0 vote178 views1 answer
Retrofit post header
Java
2 votes306 views1 answer
Java display message
Java