Sort a list of array python

from operator import itemgetter
A = [[10, 8], [90, 2], [45, 6]]
print("Sorted List A based on index 0: % s" % (sorted(A, key=itemgetter(0))))
B = [[50, 'Yes'], [20, 'No'], [100, 'Maybe']]
print("Sorted List B based on index 1: % s" % (sorted(B, key=itemgetter(1))))

"""
Output:
Sorted List A based on index 0: [[10, 8], [45, 6], [90, 2]]
Sorted List B based on index 1: [[100, 'Maybe'], [20, 'No'], [50, 'Yes']]
"""

Source: delftstack.com

How to sort a list in python

l=[1,3,2,5]
l= sorted(l)
print(l)
#output=[1, 2, 3, 5]
#or reverse the order:
l=[1,3,2,5]
l= sorted(l,reverse=True)
print(l)
#output=[5, 3, 2, 1]

Similar codes

2 votes289 views1 answer
Pandas remame a no name column
Python
1 vote321 views2 answers
Can you look for specific characters in python
Python
23 votes350 views1 answer
How to extract month from date in python
Python
0 vote343 views1 answer
Get or create django
Python Django
0 vote294 views1 answer
Python ssl module is not available
Python
5 votes297 views1 answer
How to get a dataframe column as a list
Python
0 vote367 views1 answer
Setting up a django prostgress project
Python Django
0 vote295 views1 answer
Numpy is not nan
Python
0 vote315 views1 answer
Plot every nth label in barplot
Python
0 vote292 views1 answer
Find highest correlation pairs pandas
Python