Sort a list of array python

from operator import itemgetter
A = [[10, 8], [90, 2], [45, 6]]
print("Sorted List A based on index 0: % s" % (sorted(A, key=itemgetter(0))))
B = [[50, 'Yes'], [20, 'No'], [100, 'Maybe']]
print("Sorted List B based on index 1: % s" % (sorted(B, key=itemgetter(1))))

"""
Output:
Sorted List A based on index 0: [[10, 8], [45, 6], [90, 2]]
Sorted List B based on index 1: [[100, 'Maybe'], [20, 'No'], [50, 'Yes']]
"""

Source: delftstack.com

How to sort a list in python

l=[1,3,2,5]
l= sorted(l)
print(l)
#output=[1, 2, 3, 5]
#or reverse the order:
l=[1,3,2,5]
l= sorted(l,reverse=True)
print(l)
#output=[5, 3, 2, 1]

Similar codes

-1 vote281 views1 answer
Sort dict based on other list
Python
2 votes253 views1 answer
Python finally keyword
Python
1 vote246 views1 answer
Fake migration
Python
0 vote250 views1 answer
Django model make the field caseinsensitive
Python
0 vote246 views1 answer
Python how to import library absoluth path
Python
95 votes260 views6 answers
Get working directory python
Python
0 vote273 views1 answer
Django querset group by sum
Python Django
0 vote206 views1 answer
Pytorchvideo cant pickle local object 'kinetics data module.val dataloader.<locals>.<lambda>'
Python
0 vote276 views2 answers
Find index of null values pandas
Python
28 votes262 views3 answers
Datetime one month ago python
Python