/Python/Sorting a dictionary by value in python

Sorting a dictionary by value in python

How can I sort a dictionary in python according to its values?

s = {1: 1, 7: 2, 4: 2, 3: 1, 8: 1}
k = dict(sorted(s.items(),key=lambda x:x[0],reverse = True))
print(k)

Sorting a dictionary by value in python

x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
{k: v for k, v in sorted(x.items(), key=lambda item: item[1])}
{0: 0, 2: 1, 1: 2, 4: 3, 3: 4}

Source: stackoverflow.com

Python - sort dictionary by value

d = {'one':1,'three':3,'five':5,'two':2,'four':4}

# Sort
a = sorted(d.items(), key=lambda x: x[1])

# Reverse sort
r = sorted(d.items(), key=lambda x: x[1], reverse=True)

Source: stackoverflow.com

Sort dictionary

#for dictionary d
sorted(d.items(), key=lambda x: x[1]) #for inceasing order
sorted(d.items(), key=lambda x: x[1], reverse=True) # for decreasing order
#it will return list of key value pair tuples

Similar codes

21 votes198 views1 answer
Python date now plus days
Python
0 vote205 views1 answer
Django email change sender name
Python
5 votes200 views6 answers
Python epoch to datetime
Python
0 vote223 views1 answer
Flask new response style with `make_response`
Python Flask
0 vote208 views1 answer
Pillow python update image
Python
1 vote203 views2 answers
Location of python in cmd
Python
14 votes203 views5 answers
Read excel sheet in python
Python
16 votes186 views1 answer
Super idol
Python
0 vote198 views1 answer
How to print class attributes in python
Python
15 votes201 views3 answers
Group by 2 columns pandas
Python