C to c++ code converter

Convert c++ code to c online

#include<stdio.h>

C to c++ code converter

#include <stdio.h>
#define SIZEX 19
#define SIZEY 22
#define SIZEZ 23

int maj(int, int, int);

int main(){
        int x[SIZEX] = {1,0,1,0,1,0,1,0,1,0,1,0,1,0,1,0,1,0,1};
        int y[SIZEY] = {1,1,0,0,1,1,0,0,1,1,0,0,1,1,0,0,1,1,0,0,1,1};
        int z[SIZEZ] = {1,1,1,0,0,0,0,1,1,1,1,0,0,0,0,1,1,1,1,0,0,0,0};

C to c++ code converter

   int i,j = 0;
        int m;

        printf("\n");
        for(i = 0; i < 9; i++){
                m  = maj(x[8], y[10], z[10]);

                printf("X: ");
                if(x[8] == m){
                        int t = x[13] ^ x[16] ^ x[17] ^ x[18];
                        for(j = SIZEX-1 ; j >= 0; j--){
                                if(j == 0){
                                        x[j] = t;
                                }else{
                                        x[j] = x[j-1];
                                }

                        }
                }

C to c++ code converter

#include <stdio.h>
#define SIZEX 19
#define SIZEY 22
#define SIZEZ 23

int maj(int, int, int);

int main(){
        int x[SIZEX] = {1,0,1,0,1,0,1,0,1,0,1,0,1,0,1,0,1,0,1};
        int y[SIZEY] = {1,1,0,0,1,1,0,0,1,1,0,0,1,1,0,0,1,1,0,0,1,1};
        int z[SIZEZ] = {1,1,1,0,0,0,0,1,1,1,1,0,0,0,0,1,1,1,1,0,0,0,0};

C code to c++ converter

#include <stdio.h>
main ( )
{
char op ;
int n1, n2 ;
printf ("opération souhaitée (+ ou *) ?\n ") ;
scanf ("%c", &op) ;
printf ("donnez 2 nombres entiers : \n") ;
scanf ("%d %d", &n1, &n2) ;
if (op == '+')
printf ("leur somme est : %d \n", n1+n2) ;
else
printf ("leur produit est : %d \n",n1*n2) ;
getch ( ); } //

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