Java regex ip

Java ip regex pattern

String pattern = "([01]?[0-9]{1,2}|2[0-4][0-9]|25[0-5])";

Java regex ip

public static boolean isIP(String ip)  {
    Pattern p = Pattern.compile("(([01]?[0-9]{1,2}|2[0-4][0-9]|25[0-5])\\.){3}([01]?[0-9]{1,2}|2[0-4][0-9]|25[0-5])");
    Matcher m = p.matcher(ip);
    return m.matches();
}

Source: farenda.com

Similar codes

0 vote238 views1 answer
Can a java class have more than 108 constructors
Java
0 vote276 views1 answer
Authentication in spring boot
Java Spring
2 votes244 views1 answer
Java file existing check
Java
1 vote239 views1 answer
Initialize array with values java
Java
0 vote257 views1 answer
Fab to CircularRevealFrameLayout example
Java
0 vote262 views1 answer
Plus one leetcode
Java
4 votes251 views3 answers
Exit app android
Java
2 votes229 views1 answer
Listview get selected java
Java
0 vote257 views1 answer
Hackerrank valid username regular expression
Java
1 vote257 views1 answer
30/8
Java