Python regex for a url

import re

url = '<p>Hello World</p><a href="http://example.com">More Examples</a><a href="http://example2.com">Even More Examples</a>'

urls = re.findall('https?://(?:[-\w.]|(?:%[\da-fA-F]{2}))+', url)

>>> print urls
['http://example.com', 'http://example2.com']

Source: stackoverflow.com

Similar codes

0 vote337 views1 answer
How to read frame width of video in cv2
Python
3 votes335 views1 answer
Numpy factorial
Python
-4 votes341 views4 answers
Django latest version
Python
1 vote337 views1 answer
How to make markdown cell in jupyter notebook
Python
0 vote298 views1 answer
Download face_cascade.detectMultiScale
Python
0 vote302 views1 answer
Range endpoint
Python
5 votes356 views4 answers
Create python list
Python
1 vote315 views1 answer
How to make a tick update in python
Python
52 votes313 views6 answers
Python virtual enviroment
Python
80 votes308 views3 answers
Python remove last part of string
Python