Python regex for a url

import re

url = '<p>Hello World</p><a href="http://example.com">More Examples</a><a href="http://example2.com">Even More Examples</a>'

urls = re.findall('https?://(?:[-\w.]|(?:%[\da-fA-F]{2}))+', url)

>>> print urls
['http://example.com', 'http://example2.com']

Source: stackoverflow.com

Similar codes

2 votes163 views3 answers
Python random number generator no duplicates
Python
0 vote185 views1 answer
Django retrieveupdatedestroyapiview
Python Django
69 votes182 views3 answers
Reverse the words in a string python
Python
0 vote176 views1 answer
Python - find columns that are objects
Python
0 vote184 views1 answer
Python float to string n decimals
Python
0 vote194 views1 answer
Invalid comparison between dtype=datetime64[ns] and date filter
Python
0 vote183 views1 answer
Pysimplegui themes
Python
0 vote159 views1 answer
Add label to colorbar
Python
30 votes170 views3 answers
Django create superuser from script
Python
4 votes176 views2 answers
Plot distribution seaborn
Python