Python regex for a url

import re

url = '<p>Hello World</p><a href="http://example.com">More Examples</a><a href="http://example2.com">Even More Examples</a>'

urls = re.findall('https?://(?:[-\w.]|(?:%[\da-fA-F]{2}))+', url)

>>> print urls
['http://example.com', 'http://example2.com']

Source: stackoverflow.com

Similar codes

1 vote120 views2 answers
No changes detected in app django
Python
1 vote108 views1 answer
Maximo numero de variables dentro de un .def python
Python
0 vote113 views1 answer
Compile and train cnn models
Python
2 votes113 views1 answer
Python buffer
Python
1 vote125 views3 answers
How to add items to tuple in python
Python
0 vote117 views1 answer
Python enumerate to skip items
Python
10 votes115 views5 answers
Pandas convert float to int
Python
0 vote121 views1 answer
Python getter decorator
Python
6 votes123 views3 answers
Pandas drop row by condition
Python
2 votes117 views2 answers
Check all python versions ubuntu
Python