Catch error python

import traceback

dict = {'a':3,'b':5,'c':8}
try:
  print(dict[q])
 
except:
  traceback.print_exc()
  
# This will trace you back to the line where everything went wrong. 
# So in this case you will get back line 5

Catch error data with except python

import sys
try:
	S = 1/0 #Create Error
except: # catch *all* exceptions
    e = sys.exc_info()
    print(e) # (Exception Type, Exception Value, TraceBack)

############
#    OR    #
############
try:
	S = 1/0
except ZeroDivisionError as e:
    print(e) # ZeroDivisionError('division by zero')

Similar codes

0 vote328 views1 answer
Robust scaler
Python
0 vote329 views2 answers
Send message from server to client python
Python
0 vote342 views1 answer
Macos youtube-dl unable to get local issuer certificate _ssl.c:1131
Python
1 vote312 views1 answer
Prevent list index out of range python
Python
0 vote342 views1 answer
Django file field from base64
Python Django
0 vote296 views1 answer
Cv2 open blank window
Python
0 vote328 views1 answer
Ex: python
Python
0 vote334 views1 answer
Funny application in python
Python
10 votes340 views4 answers
How to know if python is 64 or 32 bit
Python
1 vote368 views2 answers
Remove first element from list
Python