Catch error python

import traceback

dict = {'a':3,'b':5,'c':8}
try:
  print(dict[q])
 
except:
  traceback.print_exc()
  
# This will trace you back to the line where everything went wrong. 
# So in this case you will get back line 5

Catch error data with except python

import sys
try:
	S = 1/0 #Create Error
except: # catch *all* exceptions
    e = sys.exc_info()
    print(e) # (Exception Type, Exception Value, TraceBack)

############
#    OR    #
############
try:
	S = 1/0
except ZeroDivisionError as e:
    print(e) # ZeroDivisionError('division by zero')

Similar codes

0 vote171 views1 answer
Write page source to text file python
Python
0 vote180 views1 answer
Python csv find specific string
Python
0 vote173 views1 answer
Bar chart with x-ticks
Python
0 vote192 views1 answer
Python youtube downloader github
Python
0 vote165 views1 answer
How to make images in python
Python
25 votes158 views3 answers
Python catch all exceptions
Python
12 votes188 views10 answers
Google
Python
0 vote174 views1 answer
Python open dicom file
Python
0 vote152 views2 answers
Removing an item from a list and adding it to another list python
Python
-11 votes186 views9 answers
çeviri
Python