Retrieve row by index pandas

Pandas select row by index

#for single row
df.loc[ index , : ]

# for multiple rows
indices = [1, 20, 33, 47, 52 ]
new_df= df.iloc[indices, :]

Dataframe get row by name

row_data = df.loc[ 'a' , : ]

Source: thispointer.com

Isolate row based on index pandas

dfObj.iloc[: , [0, 2]]

Source: thispointer.com

Retrieve row by index pandas

rowData = dfObj.loc[ 'b' , : ]

Source: thispointer.com

Dataframe select row by index value

In [1]: df = pd.DataFrame(np.random.rand(5,2),index=range(0,10,2),columns=list('AB'))

In [2]: df
Out[2]: 
          A         B
0  1.068932 -0.794307
2 -0.470056  1.192211
4 -0.284561  0.756029
6  1.037563 -0.267820
8 -0.538478 -0.800654

In [5]: df.iloc[[2]]
Out[5]: 
          A         B
4 -0.284561  0.756029

In [6]: df.loc[[2]]
Out[6]: 
          A         B
2 -0.470056  1.192211

Source: stackoverflow.com

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